compiler: namespace type equivalence based on AST node + captures
This implements the accepted proposal #18816. Namespace-owning types (struct, enum, union, opaque) are no longer unique whenever analysed; instead, their identity is determined based on their AST node and the set of values they capture. Reified types (`@Type`) are deduplicated based on the structure of the type created. For instance, if two structs are created by the same reification with identical fields, layout, etc, they will be the same type. This commit does not produce a working compiler; the next commit, adding captures for decl references, is necessary. It felt appropriate to split this up. Resolves: #18816
This commit is contained in:
@@ -3548,12 +3548,11 @@ pub const Object = struct {
|
||||
);
|
||||
return ty;
|
||||
},
|
||||
.opaque_type => |opaque_type| {
|
||||
.opaque_type => {
|
||||
const gop = try o.type_map.getOrPut(o.gpa, t.toIntern());
|
||||
if (!gop.found_existing) {
|
||||
const name = try o.builder.string(ip.stringToSlice(
|
||||
try mod.opaqueFullyQualifiedName(opaque_type),
|
||||
));
|
||||
const decl = mod.declPtr(ip.loadOpaqueType(t.toIntern()).decl);
|
||||
const name = try o.builder.string(ip.stringToSlice(try decl.getFullyQualifiedName(mod)));
|
||||
gop.value_ptr.* = try o.builder.opaqueType(name);
|
||||
}
|
||||
return gop.value_ptr.*;
|
||||
|
||||
Reference in New Issue
Block a user