use * for pointer type instead of &

See #770

To help automatically translate code, see the
zig-fmt-pointer-reform-2 branch.

This will convert all & into *. Due to the syntax
ambiguity (which is why we are making this change),
even address-of & will turn into *, so you'll have
to manually fix thes instances. You will be guaranteed
to get compile errors for them - expected 'type', found 'foo'
This commit is contained in:
Andrew Kelley
2018-05-31 10:56:59 -04:00
parent 717ac85a5a
commit fcbb7426fa
150 changed files with 2160 additions and 2141 deletions

View File

@@ -11,12 +11,12 @@ const B = struct {
const C = struct {
x: i32,
fn d(c: &const C) i32 {
fn d(c: *const C) i32 {
return c.x;
}
};
fn foo(a: &const A) i32 {
fn foo(a: *const A) i32 {
return a.b.c.d();
}