use * for pointer type instead of &
See #770 To help automatically translate code, see the zig-fmt-pointer-reform-2 branch. This will convert all & into *. Due to the syntax ambiguity (which is why we are making this change), even address-of & will turn into *, so you'll have to manually fix thes instances. You will be guaranteed to get compile errors for them - expected 'type', found 'foo'
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@@ -11,12 +11,12 @@ const B = struct {
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const C = struct {
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x: i32,
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fn d(c: &const C) i32 {
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fn d(c: *const C) i32 {
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return c.x;
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}
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};
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fn foo(a: &const A) i32 {
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fn foo(a: *const A) i32 {
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return a.b.c.d();
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}
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