use * for pointer type instead of &
See #770 To help automatically translate code, see the zig-fmt-pointer-reform-2 branch. This will convert all & into *. Due to the syntax ambiguity (which is why we are making this change), even address-of & will turn into *, so you'll have to manually fix thes instances. You will be guaranteed to get compile errors for them - expected 'type', found 'foo'
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@@ -2,13 +2,13 @@ const std = @import("std");
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const assert = std.debug.assert;
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test "struct contains null pointer which contains original struct" {
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var x: ?&NodeLineComment = null;
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var x: ?*NodeLineComment = null;
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assert(x == null);
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}
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pub const Node = struct {
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id: Id,
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comment: ?&NodeLineComment,
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comment: ?*NodeLineComment,
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pub const Id = enum {
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Root,
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