use * for pointer type instead of &

See #770

To help automatically translate code, see the
zig-fmt-pointer-reform-2 branch.

This will convert all & into *. Due to the syntax
ambiguity (which is why we are making this change),
even address-of & will turn into *, so you'll have
to manually fix thes instances. You will be guaranteed
to get compile errors for them - expected 'type', found 'foo'
This commit is contained in:
Andrew Kelley
2018-05-31 10:56:59 -04:00
parent 717ac85a5a
commit fcbb7426fa
150 changed files with 2160 additions and 2141 deletions

View File

@@ -2,13 +2,13 @@ const std = @import("std");
const assert = std.debug.assert;
test "struct contains null pointer which contains original struct" {
var x: ?&NodeLineComment = null;
var x: ?*NodeLineComment = null;
assert(x == null);
}
pub const Node = struct {
id: Id,
comment: ?&NodeLineComment,
comment: ?*NodeLineComment,
pub const Id = enum {
Root,